![]() For example, for there were 20 payments so, the percentage of successful payments = 50%, failed = 25% and refunded = 25%. The query successfully returns how many payments were processed on each day and the status:, successful, 10īut I don't know how to make it calculate the percentage for each payment for each day. Using CTE How does the limit clause work in MySQL MySQL supports the LIMIT clause to select a limited number of records, while Oracle uses FETCH FIRST n ROWS ONLY and ROWNUM. Please show an example of the desired output if you want us to give a meaningful answer. There are different ways to calculate percentage in SQL like: 1. My current query is this: select pdate, status, count(*) as total Syntax The basic syntax for the count function is: COUNT() COUNT( expression) COUNT( DISTINCT expression ) Explanation: The function has three forms explained as follows: COUNT () function: It returns all the number of rows in a table returned by the SELECT query, including non-NULL, NULL, and duplicate rows from the table. 1 The two queries aren't compatible, as they're currently written: One returns a single record with a single column, the other will return many columns in X rows. ![]() I need to write a query to get, for each day how many payments were successful, how many failed and how many were refunded, with the percentage for that day. So again, the above statement will count only the rows where neither col1 nor col2 is null.I have a payments table with the following fields: Adding up ( SUM) the 1s is equivalent to counting the truths. With only 1s and 0s the * operator works as an equivalent of the logical AND: the final result will be 1 (True) only if each operand is 1 otherwise the result will be 0 (False). In the context of the arithmetic operator * the logical result of the IS NOT NULL operator is implicitly converted to a number, 1 for True, 0 for False. SUM( (col1 IS NOT NULL) * (col2 IS NOT NULL) ) In particular, you could replace the COUNT with SUM and treat the predicates as numbers (1/0) in an arithmetic expression: SELECT It is possible to shorten the expression somewhat by choosing a less clear syntax. Perhaps the next option will be more to your liking. ![]() Unfortunately, that's not easily done using the over () clause. The obvious flaw of this workaround (either variation) is that it is clearly rather unwieldy and will become ridiculously long very quickly as you add more columns to account for. Here's the formula to obtain a percentage: count () 100.0 / sum (count ()) over () Adding the above SQL to our original query produces the following results: Looks good, but some rounding wouldn't hurt. A row will be counted only if neither col1 nor col2 is null. Where instead of the 1 you can put any non-null constant. Or the MySQL-specific IF function: SELECTĬOUNT(IF(col1 IS NOT NULL AND col2 IS NOT NULL, 1, NULL)) Here are three suggestions: select coalesce (p.psarea,p1.psarea) as psarea, Male, Female from ( select psarea, count () as Male from personal where psgender 'M' group by psarea ) as p full outer join ( select psarea, count () as Female from personal where psgender 'F' group by psarea ) as p1 on p1.psarea p. ![]() ![]() It could be either the standard-compliant CASE: SELECTĬOUNT(CASE WHEN col1 IS NOT NULL AND col2 IS NOT NULL THEN 1 END) So: SELECT SUM (resolution'Cancelled')100/count () FROM table. resolution'Cancelled' is an expression returning 0 for false, or 1 for true. Example Code: SELECT RepresentativeName, Sale, round( ( (Sale 100) / temp. If that last aspect of the behaviour is what you are trying to achieve, you could emulate it using a conditional inside COUNT. To get the percentage you need to divide the sum of the value, with the total and multiply by 100 to get a percentage. To find the percentage of the Sale field, we can CROSS JOIN the SUM () function of the Sale attribute with the original relation (table). 1 Answer Sorted by: 1 To get the percentage you need to divide the sum of the value, with the total and multiply by 100 to get a percentage. However, one other important point is that a tuple is counted only if none of the individual values in the tuple is null. Calculate Percentage in MySQL Query Ask Question Asked 9 years, 11 months ago Modified 9 years, 11 months ago Viewed 10k times 0 I am trying to produce a MySQL table that contains a column displaying the percentage corresponding to one count over another with the same grouping. I have a table named PERSON (In the live system I expect several hundred thousand records or more). Obviously, COUNT(DISTINCT) with multiple columns counts unique combinations of the specified columns' values. I am using MySQL and I need help using COUNT() for a range of values within a table. ![]()
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